30x^2+55x=50

Solution for 30x^2+55x=50 equation:

30x^2+55x=50

We move all terms to the left:

30x^2+55x-(50)=0

a = 30; b = 55; c = -50;
Δ = b2-4ac
Δ = 552-4·30·(-50)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-95}{2*30}=\frac{-150}{60}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+95}{2*30}=\frac{40}{60}
=2/3
$